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SQL Server存储函数的加密解密
http://www.21tx.com 2005年08月19日 软考资讯网

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  存储过程、存储函数的加密:WITH ENCRYPTION

  <!--[if !supportLineBreakNewLine]-->

  <!--[endif]-->

  CREATE procedure dbo.sp_XML_main

  @table_name nvarchar(260)='',

  @dirname nvarchar(20)=''

  WITH ENCRYPTION

  as

  begin

  ....................................................

  end

  go

  存储过程、存储函数的解密(以下是一位绝世高人编写的代码)

  if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[sp_decrypt]') and OBJECTPROPERTY(id, N'IsProcedure') = 1)

  drop procedure [dbo].[sp_decrypt]

  GO

  /*--破解函数,过程,触发器,视图.仅限于SQLSERVER2000

  --作者:J9988--*/

  /*--调用示例

  --解密指定存储过程

  exec sp_decrypt 'AppSP_test'

  --对所有的存储过程解密

  declare tb cursor for

  select name from sysobjects where xtype='P' and status>0 and name<>'sp_decrypt'

  declare @name sysname

  open tb

  fetch next from tb into @name

  while @@fetch_status=0

  begin

  print '/*-------存储过程 ['+@name+'] -----------*/'

  exec sp_decrypt @name

  fetch next from tb into @name

  end

  close tb

  deallocate tb

  --*/

  if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[SP_DECRYPT]') and OBJECTPROPERTY(id, N'IsProcedure') = 1)

  drop procedure [dbo].[SP_DECRYPT]

  GO

  CREATE PROCEDURE sp_decrypt(@objectName varchar(50))

  AS

  begin

  set nocount on

  --CSDN:j9988 copyright:2004.04.15

  --V3.1

  --破解字节不受限制,适用于SQLSERVER2000存储过程,函数,视图,触发器

  --修正上一版视图触发器不能正确解密错误

  --发现有错,请E_MAIL:CSDNj9988@tom.com

  begin tran

  declare @objectname1 varchar(100),@orgvarbin varbinary(8000)

  declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)

  DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)

  declare @i int,@status int,@type varchar(10),@parentid int

  declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int

  select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)

  create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)

  insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)

  select @number=max(number) from #temp

  set @k=0

  while @k<=@number

  begin

  if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)

  begin

  if @type='P'

  set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS '

  else 'ALTER PROCEDURE '+ @objectName+' WITH ENCRYPTION AS '

  end)

  if @type='TR'

  begin

  declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)

  select @parent_obj=parent_obj from sysobjects where id=object_id(@objectName)

  select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj

  if @tr_parent_xtype='V'

  begin

  set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1 '

  end

  else

  begin

  set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '

  end

  end

  if @type='FN' or @type='TF' or @type='IF'

  set @sql1=(case @type when 'TF' then

  'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '

 

  when 'FN' then

  'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns char(1) with encryption as begin return @a end'

  when 'IF' then

  'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns table with encryption as return select @a as a'

  end)

  if @type='V'

  set @sql1='ALTER VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'

  set @q=len(@sql1)

  set @sql1=@sql1+REPLICATE('-',4000-@q)

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